To identify a pattern in a partial string, use the FindPattern function to either return a Passed/Failed status or the content of the matched string. The relative sections below describe how to implement this.
Returning a Passed/Failed Status
- In the Sequence, create the following Local Variables:
- a String called Str1. Set the value to the string to be compared.
- a String called Str2. Set the value to a Regular Expression.
- a Number called PatternLength.
- Place a Pass/Fail Test Step in the Sequence.
- In the Data Source tab, enter Step.Result.PassFail. This will use the step result as the pass/fail comparison.
- In the Properties tab, click on the Expressions option.
- In the Pre-Expression input, enter the expression below. This will store the result of FindPattern in the step's Data Source variable.
Step.Result.PassFail = FindPattern(Locals.Str1, Locals.Str2, 0, True, Locals.PatternLength) == 1 ? False:True
Returning a Matched String
- In the Sequence, create the following Local Variables:
- a String called Str1. Set the value to the string to be compared.
- a String called Str2. Set the value to the Regular Expression.
- a Number called FoundIndex.
- a Number called PatternLength.
- Place a Statement Step.
- Enter the following statement:
Locals.FoundIndex = FindPattern(Locals.Str1, Locals.Str2, 0, True, Locals.PatternLength)
- Place a Message Popup Step.
- In the Text and Buttons tab, enter the following Message Expression.
- This uses the Mid function to retrieve the matching sub-string from Locals.Str1.
"The matched string is " + Mid(Locals.Str1, Locals.FoundIndex, Locals.PatternLength)