Using shared variables to store mapsIf the original variant contains a map and you store it on a shared variable, when you pass the shared variable to the Variant to Data VI to try to extract the map from the variant, you will receive this error. This happens because shared variables currently can't store maps. Even though the shared variable can store a variant, at the end, the variant contains the original data, which in this case is a map. To work around this limitation, you can use different data structure (array or cluster) or separate out the keys and values of the map and rebuild the map after passing the data through the shared variables.
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